Question

find the roots of the quadratic equation 2x2-7x+3=0​

Answer 1

your question....

2x²-7x+3=0

x=-b+_√b²-4ac/2a

x=7+_√49-24/4

x=7+_√25/4

x=7+_5/4

x=1/2,3

this is your answer..

Answer 2

The correct answer is "x=1/3" and "x=3".

Step-by-step explanation:

$The \ given \ equation \ is:\\2x^2-7x+3=0\\On \ subtracting \ the \ given \ equation,we \ get\\2x^2-6x-x+3=0\\2x(x-3)-1(x-3)=0\\(2x-1)(x-3)=0\\2x-1=0\\2x=1\\x=\frac{1}{3}\\ Or,\\x-3=0\\x=3$

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