Question

Find the roots of the quadratic equation 3 x2 - 2√6x + 2 = 0.​

Answer 1

Answer:

$x = \frac{2}{ \sqrt{6} } .$

Step-by-step explanation:

$3 {x}^{2} - 2 \sqrt{6} x + 2 = 0 \\ \\ d = {(2 \sqrt{6}) }^{2} - 4(3 \times 2) \\ \\ = 24 - 24 = 0 \\ \\ x = \frac{ - ( - 2 \sqrt{6}) + 0 }{2 \times 3} \\ \\ x = \frac{ 2\sqrt{6} }{6} \\ \\ x = \frac{2}{ \sqrt{6} } .$