Question

Find the roots of the quadratic equation 3x²-2✓6x+2=0

Answer 1

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Still Good Morning

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We have

=> 3x² - 2√6x + 2 = 0

=> 3x² - √6x - √6x + 2 = 0

=> √3x(√3x - √2) - √2(√3x - √2) = 0

=> (√3x - √2)(√3x - √2) = 0

=> (√3x - √2)² = 0

=> √3x = √2

=> x = √2/√3 and x = √2/√3

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Hope this helps ✌️

Answer 2

3x² - 2√6x + 2 = 0

=> 3x² - √6x - √6x + 2 = 0

=> √3x(√3x - √2) - √2(√3x - √2)

=> (√3x - √2)(√3x - √2)

$x = \sqrt{ \dfrac{2}{3} } \: and \: \sqrt{ \dfrac{2}{3} }$