Question

find the roots of the quadratic equation 4√3x^2+5x-2√3=0 by factorisation method​

Answer 1

Answer:

-2/✓3 , ✓3/4

Step-by-step explanation:

I hope you got answer

Answer 2

$Given \: 4\sqrt{3}x^{2}+5x - 2\sqrt{3} = 0$

/* Splitting the middle term,we get */

$\implies 4\sqrt{3}x^{2}+8x-3x - 2\sqrt{3} = 0$

$\implies 4x(\sqrt{3}x+2) - \sqrt{3}(\sqrt{3}x +2) = 0$

$\implies (\sqrt{3}x+2)(4x-\sqrt{3}) = 0$

$\implies \sqrt{3}x+2= 0 \: Or \: 4x-\sqrt{3} = 0$

$\implies \sqrt{3}x = -2 \: Or \: 4x=\sqrt{3}$

$\implies x = \frac{ -2}{ \sqrt{3}}\: Or \: x=\frac{\sqrt{3}}{4}$

Therefore.,

$\green {x = \frac{ -2}{ \sqrt{3}}\: Or \: x=\frac{\sqrt{3}}{4}}$

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