Find the roots of the quadratic equation 4x^2+4bx-(a2-b2)
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4x^2+4bx-(a2-b2) =0
=> 4x²+4bx-(a+b)(a-b)=0
=> 4x²+2(a+b)x-2(a-b)x-(a+b)(a-b)=0
=>2x[2x+a+b]-(a-b)[2x+a+b]=0
=> (2x+a+b)[2x-(a-b)]=0
=> 2x+a+b=0 or 2x-(a-b)=0
=> 2x= -(a+b) or 2x= (a-b)
=> x = -(a+b)/2 or x = (a-b)/2
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