Question

| Find the roots of the quadratic equation 6x2 - √2x - 2 = 0​

Answer 1

EXPLAINED CLEARLY IN THE PICTURE

HOPE IT HELPS.....

PLS MARK AS BRAINLIEST

Answer 2

${\bold{\underline{\underline{Answer:}}}}$

$\\{\bold{\therefore x=\frac{\sqrt{2}\pm\sqrt{50}}{12}}}$

${\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about a quadratic equation.

• We have to find the value of x from the given quadratic equation :

$\underline{ \underline \bold{Given : }} \\ \implies x \in(6 {x}^{2} - \sqrt{2} x - 2 = 0) \\ \\ \underline{ \underline \bold{To \: Find : }} \\ \implies x = ?$

• According to given question :

$\implies 6{x}^{2} - \sqrt{2}x - 2 = 0 \\ \\ \bold{Using \: Quadratic \: formula : } \\ \implies x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ \implies x = \frac{ - ( - \sqrt{2}) \pm \sqrt{ {( \sqrt{2}) }^{2} - 4 \times 6 \times - 2 } }{2 \times 6} \\ \\ \implies x = \frac{ \sqrt{2} \pm \sqrt{2 + 48} }{12} \\ \\ \bold{\implies x = \frac{ \sqrt{2} \pm \sqrt{50} }{12 } }$