Question

find the roots of the quadratic equation a2b2x2+b2x-a2x-1=0

Answer 1

Answer:

a2b2x2+b2x-a2x-1=0

a2x (b2x-1) + 1 (b2x-1)

(a2x+1) (b2x-1)

x=     -1/a2  , 1/b2

Step-by-step explanation:

Answer 2

Answer:

${a}^{2} {b}^{2} {c}^{2} + {b}^{2}x - {a}^{2} x - 1 = 0$

${b}^{2} x( {a}^{2} + 1) - 1( {a}^{2}x + 1) = 0$

$( {b}^{2} x - 1)( {a}^{2} x + 1) = 0$

$Therefore, x = \frac{1}{ {b}^{2} } ,\: \frac{ - 1}{ {a}^{2} }$

I Hope It Will Help!

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