Question

find the roots of the quadratic equation by factorization method 6 x square - root 2x-2=0

Answer 1

$6 {x}^{2} - \sqrt{2} x - 2 = 0 \\ \\ 6 {x}^{2} - 3 \sqrt{2} x + 2 \sqrt{2} x - 2 = 0 \\ \\ 3 \sqrt{2} x( \sqrt{2} x - 1) + 2( \sqrt{2} x - 1) = 0 \\ \\ ( \sqrt{2} x - 1)(3 \sqrt{2} x + 2) = 0 \\ \\ \\ \\ x = \frac{1}{ \sqrt{2} } \: and \: \frac{ - 2}{3 \sqrt{2} } = \frac{ - \sqrt{2} }{3}$

Answer 2

Hope this helps you...