Question

find the roots of the quadratic equation:n²+3n+2​

Answer 1

n²+3n+2

=> n² + n + 2n +2

=> n(n+1) + 2 (n+1)

=>( n+2)(n+1)

Now,

n²+3n+2 will be 0

when, ( n+2)(n+1) = 0

=> n+2 =0. or. n+1= 0

=>. n= -2 => n=-1

so, n = -2 and -1

So the zeros of the quadratic equation are -2 and -1 .