Find the roots of the quadratic equation root3xsquare-2x-root3=0
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= root 3 x square - 3 x + X - root 3 = 0
= root 3 x( x minus root 3) + 1 (x minus root 3)=0
= (x - root 3 )(root 3 x + 1 ) = 0
= roots are = root 3 and -1/root3
= root 3 x( x minus root 3) + 1 (x minus root 3)=0
= (x - root 3 )(root 3 x + 1 ) = 0
= roots are = root 3 and -1/root3
kumarsunny39p365m3:
Again Thank's Sanjana jee
again welcum
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