Question

Find the roots of the quadratic equation
$\sqrt{3} { \times }^{2} + 2x - \sqrt{3} = 0$

Answer 1

[tex] \sqrt[]{3} {x}^{2} + 2x - \sqrt{3} = 0 \\ \sqrt{3} {x}^{2} + 3x - x - \sqrt{3} = 0 \\ \sqrt{3}x ( {x} \: + \sqrt{3} ) - 1(x + \sqrt{3} ) = 0 \\( x + \sqrt{3} )( \sqrt{3} - x) = 0 \\ x + \sqrt{3} = 0 \\ x = - \sqrt{3} \\ sqrt3-x=0
X=-sqrt3

Answer 2

HEYA USER ✌

HERES YOUR ANSWER FRIEND,

THE GIVEN EQUATION IS

==> √3x² + 2x - √3 = 0

==> √3x² + 3x - x - √3 = 0

==> √3x( x + √3) -1 (x + √3) = 0

==> (√3x - 1)(x + √3) = 0

==> x = 1/√3 or x = -√3

HOPE IT HELPS YOU

#KANISHKA FROM KENDRIYA VIDYALAYA GANESH KHIND.

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