Question

Find the roots of the quadratic equation using quadriactic formula
4x²-4px+(p²-q²)=0​



this question is very important for me plzz give me write answer plzz....

Answer 1

Answer:

p+q/2& p-q/2

step wise explanation :

4x^2 - 4px + (p^2 - q^2) = 0

Here , a = 4 , b = -4p , c = p^2 - q^2

D = b^2 - 4ac

D = ( -4p )^2 - 4 (4) ( p^2 - q^2 )

D = 16 p^2 - 16 p^2 + 16 q^2

D = 16 q^2

x = - b _+√D / 2a

x = -( -4p ) +_ √16q^2 / 2(4)

x = 4p +_ 4q / 8

x = 4(p+_q) / 8

x = p+_q / 2

Either

x = p+q/2 OR x= p-q/2

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