Question

find the roots of the quadratic equation √x /2 + 16/x√x = 6/√x​

Answer 1

Answer:

$\frac{ \sqrt{x} }{2} + \frac{16}{x \sqrt[]{x} } = \frac{6}{ \sqrt{x} }$

$\frac{ \sqrt{x} \times x \sqrt{x} + 16 \times 2 }{2x \sqrt{x} } = \frac{6}{ \sqrt{x} }$

${x}^{2} + 32 = \frac{12x \sqrt{x} }{ \sqrt{x} }$

${x}^{2} + 32 = 12x$

${x}^{2} - 12x + 32 = 0$

${x}^{2} - 8x - 4x + 32 = 0$

$x(x - 8) - 4(x - 8)$

$(x - 8)(x - 4)$

$x = 8....or...x = 4$

Step-by-step explanation:

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