Question

find the roots of the quadratic equation x^2-5x+4=0​

Answer 1

Step-by-step explanation:

x =

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

2

−

5

+

4

=

0

x^{2}-5x+4=0

x2−5x+4=0

=

1

a={\color{#c92786}{1}}

a=1

=

−

5

b={\color{#e8710a}{-5}}

b=−5

=

4

c={\color{#129eaf}{4}}

c=4

=

−

(

−

5

)

±

(

−

5

)

2

−

Answer 2

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