Question

Find the roots of the quadratic equations by factorisation:√3x²-7x-6√3=0​

Answer 1

Answer:

$\sqrt{3} {x}^{2} - 9x + 2x - 6 \sqrt{3} = 0 \\ \sqrt{3} x(x - 3 \sqrt{3} ) + 2(x - 3 \sqrt{3} ) = 0 \\ (\sqrt{3} x + 2)(x - 3 \sqrt{3} ) = 0 \\ x = - \frac{2}{ \sqrt{3} } \: and \: x = 3 \sqrt{3}$