Question

Find the roots of the quadratic equations given in by applying the quadratic formula.(x)2-8x-180=0

Answer 1

Hi friend!!

Given quadratic equation x²-8x-180=0 ,when we compare this equation with the standard quadratic equation ax²+bx+c=0

We get, a=1,b=-8,c=-180

Roots are given by (-b±√(b²-4ac))/2a

=(8±√(64+720))/2

=(8±√784)/2

=(8±28)/2

=36/2,-20/2

=18,-10

I hope this will help you ;)

Answer 2

Concept:

An algebraic expression of the second degree in $x$ is called a quadratic equation, $ax^2+bx+c=0$ .The values of x that fulfill the equation are known as solutions of the equation, and the roots or zeros of the expression on the left-hand side are known as roots or zeros of the expression. It has only two solutions to a quadratic equation. It is said to be a double root if there is just one solution.

Given:

The quadratic equation, $x^2-8x-180=0$.

Find:

The roots of the quadratic equation.

Solution:

Solving the quadratic equation,

$x^2-8x-180=0\\x^2-18x+10x-180=0\\x(x-18)+10(x-18)=0\\(x-18)(x+10) = 0\\x = 18, -10$

Hence, the roots of the given quadratic equation are $18, -10$.