find the roots of the quadratic equations of 4x2-4px+(p2-q2)=0 by factorisation method
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hi raa boffune wast fellow
Step-by-step explanation:
Answered by
0
Answer:
Step-by-step explanation:
4x^2 - 4px + (p^2 - q^2) = 0
Here , a = 4 , b = -4p , c = p^2 - q^2
D = b^2 - 4ac
D = ( -4p )^2 - 4 (4) ( p^2 - q^2 )
D = 16 p^2 - 16 p^2 + 16 q^2
D = 16 q^2
x = - b _+√D / 2a
x = -( -4p ) +_ √16q^2 / 2(4)
x = 4p +_ 4q / 8
x = 4(p+_q) / 8
x = p+_q / 2
Either
x = p+q/2 OR x= p-q/2
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