Question

find the roots of the quadratic equations x^2+2√2x-6=0​

Answer 1

Answer

r+2/2x-6=0

+22x-V2x-6=0

(r+32)-E(x+342)=

(r+3 (T-V)=o

x+3/2 =0 or x-2 = 0

*=-3/2 or x= v2

Hence, the roots of the given

equation are-3v2 and v2.