Math, asked by shahaditya4357, 1 year ago

Find the roots of this equation 5x.sq-6x-2=o by using completing square method

Answers

Answered by Anonymous
1

Answer:

5x^2-6x -2=o

so ,

let a b are the roots of this equation

sum of roots = 6/5. (a+b)

product of roots =-2/5. (ab)

Answered by bharat9291
0

Step-by-step explanation:

5 x^2 - 6x -2 = 0

divide each tern by the coficient of x^2 that is 5

x^2 - (6/5) X - 2/5 = 0

now divide and multiply the coficient of X by 2 we get

x^2 - 2* (6/10 ) X - 2/5 = 0

now add and subtract ( 6/10 ) ^2

x^2 - 2*(6/10)*X + (6/10)^2 - ( 6/10)^2 -2/5 = 0

x^2 - 2*(6/10)X + (6/10) ^2 become ( x-6/10)^2

so

(x-6/10) ^2 - (6/10)^2 -2/5 =0

(x-6/10)^2 = (6/10)^2+2/5

( x-6/10)^2 = (36/100)+(2/5)

(x-6/10)^2 = (36+40)/100

( x-6/10) ^ 2 = 76/100 = 19/25

taking square root both sides

( x-3/5) =+- √ 19/5

X = 3/5+-√19/5

X = (3+√19)/5

or

X =( 3-√19)/5

Similar questions