Find the roots of this equation 5x.sq-6x-2=o by using completing square method
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Answered by
1
Answer:
5x^2-6x -2=o
so ,
let a b are the roots of this equation
sum of roots = 6/5. (a+b)
product of roots =-2/5. (ab)
Answered by
0
Step-by-step explanation:
5 x^2 - 6x -2 = 0
divide each tern by the coficient of x^2 that is 5
x^2 - (6/5) X - 2/5 = 0
now divide and multiply the coficient of X by 2 we get
x^2 - 2* (6/10 ) X - 2/5 = 0
now add and subtract ( 6/10 ) ^2
x^2 - 2*(6/10)*X + (6/10)^2 - ( 6/10)^2 -2/5 = 0
x^2 - 2*(6/10)X + (6/10) ^2 become ( x-6/10)^2
so
(x-6/10) ^2 - (6/10)^2 -2/5 =0
(x-6/10)^2 = (6/10)^2+2/5
( x-6/10)^2 = (36/100)+(2/5)
(x-6/10)^2 = (36+40)/100
( x-6/10) ^ 2 = 76/100 = 19/25
taking square root both sides
( x-3/5) =+- √ 19/5
X = 3/5+-√19/5
X = (3+√19)/5
or
X =( 3-√19)/5
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