Find the roots of x^2-2ax-(4b^2)=0 by using quadratic formula
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For polynomial ax²+bx+c=0
x=(-b+-√(b²-4ac))/2a
So, for polynomial x²-2ax-4b²=0
x = (2a+-√((2a)²-(4)(1)(4b²)))/(2)
x=(2a+-2√(a²-4b²))/2
x=(a+-√(a²-4b²))
x=(-b+-√(b²-4ac))/2a
So, for polynomial x²-2ax-4b²=0
x = (2a+-√((2a)²-(4)(1)(4b²)))/(2)
x=(2a+-2√(a²-4b²))/2
x=(a+-√(a²-4b²))
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