Question

find the roots of x^2+3x-28=0​

Answer 1

Answer:

Step-by-step explanation:

x²+3x-28=0

x²+7x-4x-28=0

x(x+7)-4(x+7)=0

(x-4)(x+7)=0

x-4=0,x+7=0

x=4,x=-7

Answer 2

$\huge \blue {Answer}$

✯ x²+3x-28=0

By splitting method:-

➜ x²-4x+7x-28=0

➜ x(x-4)+7(x-4)=0

➜ (x+7)(x-4)=0

➜ x+7=0; x-4=0

➜ x = -7; x = 4

Therefore roots of given equation are -7 and 4

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