Find the roots of x^2-4x-8=0
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x² - 4x -8 = 0
a = 1 b = -4 c = -8
b² - 4ac = 16 - (4*1*-8) = 48
x = (-b ± √(b² - 4ac))/2a = (4 ±√48)/2*1 = (4±4√3)/2 = 2±2√3
x = 2+2√3 or 2-2√3
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