Question

Find the roots of x^2-4x-8=0​

Answer 1

x² - 4x -8 = 0

a = 1 b = -4 c = -8

b² - 4ac = 16 - (4*1*-8) = 48

x = (-b ± √(b² - 4ac))/2a = (4 ±√48)/2*1 = (4±4√3)/2 = 2±2√3

x = 2+2√3 or 2-2√3