Question

Find the roots of x^2-x-6=0

Answer 1

Answer:

(-2), 3

Step-by-step explanation:

$x^{2}-x-6\\x^{2} -3x+2x-6\\x(x-3)+2(x-3)\\(x+2)(x-3)$

The roots are (-2), 3.

Answer 2

Step-by-step explanation:

x^2-x-6=0

x^2-3x+2x-6=0

x(x-3)+2(x-3)=0

(x-3)(x+2)=0

x-3=0. x+2=0

x=3. x=-2