Question

find the roots of x^4-2x^2+1=0
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Answer 1

jsnalaoxndn lskxnshsjs lskxnsjs

Answer 2

Answer:

Step-by-step explanation:

x^4 - 2x^2 + 1 = 0

x^2 (x^2 - 2) + 1 = 0

now outside x^2 goes under 0 in RHS because it is in multiply in LHS

x^2 - 2 + 1 = 0

x^2- 1 = 0

(x)^2 - (1)^2 = 0

(x - 1)(x + 1) = 0

it implize that ,

x = 1   OR   x = -1

therefore , 1 and -1 are required root of the equation