Find the roots of x2-2x-(r2-1)=0
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The zeroes of given equation are r+1 and 1-r
1) Given equation is x²-2x -(r²-1) = 0
2) This can be re written as x² -2x -(r+1) (r-1) = 0
3) Splitting the middle term, x² +(r-1 -1 -r)x - (r+1)(r-1) = 0
4) Simplifying, x² + (r-1)x - (r+1)x -(r-1)(r+1) = 0
5) Taking the common factors,
x(x+r-1) - (r+1)(x+r-1) = 0
(x-(r+1))(x+r-1) = 0
6) Hence, the zeroes are r+1, 1-r
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