Math, asked by ammu124, 1 year ago

Find the roots of x2-2x-(r2-1)=0

Answers

Answered by TheLostMonk
64
hye ¶ here is your answer

hope it helps
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Answered by VineetaGara
31

The zeroes of given equation are r+1 and 1-r

1) Given equation is x²-2x -(r²-1) = 0

2) This can be re written as x² -2x -(r+1) (r-1) = 0

3) Splitting the middle term, x² +(r-1 -1 -r)x - (r+1)(r-1) = 0

4) Simplifying, x² + (r-1)x - (r+1)x -(r-1)(r+1) = 0

5) Taking the common factors,

x(x+r-1) - (r+1)(x+r-1) = 0

(x-(r+1))(x+r-1) = 0

6) Hence, the zeroes are r+1, 1-r

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