Math, asked by pinky9019, 1 year ago

Find the roots of x2-3x-10=0


Sniper69: -x=10 :-P

Answers

Answered by sumanththescientist
317

 {x}^{2}  - 3x - 10 = 0 \\  {x}^{2}  - 5x + 2x - 10 = 0 \\ x(x - 5) + 2(x - 5) = 0 \\ (x - 5)(x + 2) = 0 \\ x - 5 = 0 \:  \:  \:  \:  \:  \:  or\:  \:  \:  \:  \:  \:  \:  \: x + 2 = 0 \\ x = 5 \:  \ \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \: or \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x =  - 2
please mark as brainiest please please please please
Answered by Anonymous
78
your answer:-

x2-3x-10=0

taking out factors which comes out to be -5 and 2

so

(x2-5x)+(2x-10)=0

x(x-5)+2(x-5)=0

(x+2)(x-5)=0

1) x+2=0
x=-2

2)x-5=0
x=5

answer :- -2 and 5

Sniper69: why?
Anonymous: excuse me
Anonymous: what did you write just now
Anonymous: behave yourself
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