Question

find the roots/solution of the equation y²-5y+6=o by factorisation

Answer 1

$\textbf{ \underline{ Hello Mate! }}$

y^2 - 5y + 6 = 0

y^2 - 3y - 2y + 6 = 0

y( y - 3 ) - 2( y - 3 ) = 0

( y - 2 )( y - 3 ) = 0

Each getting "0", y - 2 = 0
y =2.
Similarily, y - 3 = 0 or y = 3

$\boxed{ Solution\:for\:y=2\:or\:3 }$

Have great future ahead!

Answer 2

$\bf \large \it \: Hey \: User!!!$

given :- y² - 5y + 6

we have to find the roots of this equation by factorisation.

>> y² - 5y + 6 = 0
>> y² - ( 2y + 3y ) + 6 = 0
>> y² - 2y - 3y + 6 = 0
>> y ( y - 2 ) - 3 ( y - 2 = 0
>> ( y - 2 ) ( y - 3 )

>> ( y - 2 ) = 0
>> y = 2

or

>> ( y - 3 ) = 0
>> y = 3

hence, the roots of the equation are 2 and 3.

$\bf \large \it{Cheers!!!}$