Question

Find the roots using quadratic formula x^2 -2ax + (a^2-b^2)=0 for 10th class

Answer 1

pkease check the attachment:

Answer 2

Answer:

Step-by-step explanation:

x^2-2ax+(a^2-b^2)=0

D=b^2-4ac

=(-2a)^2-4(a^2-b^2)

=4a^2-4a^2+4b^2

=4b^2

x=-(-2a)+(√4b^2)/2. 2a-(√4b^2)/2

= a+b or a-b