Math, asked by kvkrish8531, 1 year ago

Find the rth term from the end in the expansion of (x+a)^n

Answers

Answered by taniya55555
28
\textbf{Heya Mate}

\textbf{Here is your answer }

The expansion is  {(x+a)} ^ {n}

\textbf{Now}

If the power is n then the number of terms be
n+1

Thus the rth term from the end of the expansion is =

Tn+1-r

= nCn+1-r ×  {x}^{n-n-1+r} ×  {a}^{n+1-r}

= \frac{n!}{(n+1-r)!(r-1)!} ×  {x}^{r-1} ×  {a}^{n+1-r}

\textbf{Hope this helps you }
\textbf{Be Brainly}
Answered by Shubhendu8898
21

Answer:

^nC_{n-r+1}.x^{r+1}.a^{n-r+1}

Step-by-step explanation:

We know  that,

(x+a)^n=^nC_0a^0+^nC_1\;x^{n-1}a^1...............^nC_r\;x^{n-r}a^r...........^nC_n\;x^0a^n

There are n+1 terms  in this  expansion, and the (r+1)the  term is  given by

T_{r+1}=^nC_r\;x^{n-r}a^r

the rth term from the end is  = ((n+1)-r+1) =(r-r+2)th term from the starting

\text{rth term from the end}=T_{n-r+2}\\\;\\=T_{(n-r+1)+1}\\\;\\=^nC_{n-r+1}.x^{n-n+r-1}.a^{n-r+1}\\\;\\=^nC_{n-r+1}.x^{r+1}.a^{n-r+1}

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