find the second order differentiation of the following x^2+2x=y^2
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Explanation:
x²+2x=y²
differentiate w.r.t x
=> d/dx(x²+2x)=d(y²)/dc
=> 2x+2 = 2y.dy/dx
=> (2x+2)/2y = dy/dx
=> dy/dx = (x+1)/y
again differentiate w.r.t x
=> d/dx(dy/dx) = d/dx[(x+1)/y]
=> d²y/dx²
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