Question

find the semi perimeter of a triangle whose sides are 12cm, 14cm, and 10cm​

Answer 1

Step-by-step explanation:

Semi perimeter =

$\leadsto \sf semi \: perimeter \: = \frac{a + b + c}{2} \\ \sf \leadsto \: semi \: perimeter \: = \frac{12 + 14 + 10}{2} \\ \sf \leadsto \: semi \: perimeter \: = \frac{36}{2} \\ \sf \leadsto \: semi \: perimeter \: = 18 \: ans.$

➣Note :

Here, a, b, and c represents the measure of the sides of the triangle

Answer 2

Semi perimeter = $\frac{a+b+c}{2}$ {a, b and c are the measurements of the sides of the triangle}

Semi perimeter = $\frac{12+14+10}{2}$

                           = $\frac{36}{2}$ = 18cm

Hence, the semi perimeter of the triangle is 18cm.