Question

Find the separate equation of the lines represented
by the equation 3x2 - 10xy - 8y2 = 0​

Answer 1

Answer:

0

Step-by-step explanation:

3x²-10xy-8y²=0

3x²-12xy+2xy-8y²=0

3x(x-4y)+2y(x-4y)=0

(x-4y)(3x+2y)=0

satisfaction,

3x+2y=0,x-4y=0

Answer 2

Answer:

The separate equation of the lines represented by the equation $3{x}^{2} - 10xy - {y}^{2} = 0$ are (x - 4y) = 0 and (3x + 2y) = 0

Step-by-step explanation:

Given equation is

$3{x}^{2} - 10xy - {y}^{2} = 0$

By middle term process-

$3 {x}^{2} - 12xy + 2xy - 8 {x}^{2} = 0$

[ We wrote here 10xy as (12xy-2xy)]

$3x(x - 4y) + 2y(x - 4y) = 0$

We take 3x common from first two term and 2y common from second two term.

$(x - 4y)(3x + 2y) = 0$

If multiplication of two terms is zero then they are separately zero

$(x - 4y) = 0 \: or \: (3x + 2y) = 0$

Now,Required two equations are

$(x - 4y) = 0 \: and \: (3x + 2y) = 0$