Find the seperate equation represented by the line
x^2 -2xycosecA+y^2=0
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Answer:(x−2)
2
−3(x−2)(y+1)+2(y+1)
2
=0
⇒(x−2)
2
−2×
2
3
(x−2)(y+1)+
4
9
(y+1)
2
−
4
1
(y+1)
2
=0
⇒(x−2−
2
3
(y+1))
2
−
4
1
(y+1)
2
=0
⇒
4
(2x−4−3(y+1))
2
−
4
1
(y+1)
2
=0
⇒(2x−4−3y−3−y−1)(2x−4−3y−3+y+1)=0
⇒2x−4y−8=0or2x−2y−6=0
⇒x−2y−4=0orx−y−3=0
The separate equations of the lines are x−2y=4 and x−y=3
Step-by-step explanation:
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