find the series of 1nth term when Sn=3n2+4n
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Answer:
a=7 ....it is the first term.......
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s1=3×1²+4×1
=7
so, x1=7
s2=3×2²+4×2
=3×4+8
=20
so, x2=20-7
=13
d=13-7
=6
so the series is
7,13,19,........
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