find the set of points are equidistant from the point (3,4,5) (-2,1,4)
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Answer:
the points (1,2,3) and (3,2,−1)
MEDIUM
ANSWER
Let P(x,y,z) be the point that is equidistant from points A(1,2,3) and B(3,2,−1) .
i.e. PA=PB
⇒PA
2
=PB
2
⇒(x−1)
2
+(y−2)
2
+(z−3)
2
=(x−3)
2
+(y−2)
2
+(z+1)
2
⇒x
2
−2x+1+y
2
−4y+4+z
2
−6z+9=x
2
−6x+9+y
2
−4y+4+z
2
+2z+1
⇒−2x−6z+14=−6x+2z+14
⇒−2x−6z+6x−2z=0
⇒4x−8z=0
⇒x−2z=0
Thus the required equation is x−2z=0.
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