Question

x2-5x+6=0 have
1. real and equal roots
2. real roots
3. no real root
4. real and distinct
please fast answer​

Answer 1

Answer:

Real and distinct

Step-by-step explanation:

as we know b2-4ac>0=real root and distinct

b2-4ac<0=real and equal root

b2-4ac=0=no real roots

and in this the we will put the value

a=1 , b= -5 , c=6

b2-4ac

(-5)^2 - 4(1)(6)

25-24

=1

so by this we get that

b2-4ac>0

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