Question

Find the set of value of p for which the given equation
(1 - 2p)x^2 + 8px - (2 +8p) =0 has real and equal roots​

Answer 1

1. HERE IS YOUR ANSWER :

FOR AN EQUATION HAVING REAL ROOTS,

b^2-4ac=0

b=8p

a= 1-2p

c= -(2+8p)

= -2-8p

SUBSTITUTING IN THE FORMULA

(8p)^2 - 4×(1-2p)×(-2-8p)=0

You will get the answer!!!!

Answer 2

Answer:

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