Question

Find the set of values of k for which for the equation 2x^2-10x+8=kx has no real roots

Answer 1

Answer:

» 2x² - 10x + 8 = kx

» 2x² - x (10 + k) + 8 = 0

Has no real roots,

» b² - 4ac < 0

» [-(10 + k)]² - 4 (2) (8) < 0

» (10 + k)² < 64

» 10 + k < ± 8

» k < - 2 & k < - 18

» k = (-∞, - 18)