find the seventh term from the end of the arithmetic progression 7,10 ,13...........184
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2
here a=7,,and d=10-7=3..
7th term =a+6d
7+6(3)=25
7th term =a+6d
7+6(3)=25
Anonymous:
but I asked from back
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5
Here last term = 184
d = 3
7th term from last = 184 - 6d = 184 - (6×3) = 184 -18 = 168
d = 3
7th term from last = 184 - 6d = 184 - (6×3) = 184 -18 = 168
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