find the side and diagonal of a square whose area area is 64sq cm
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let each side of the square be a
a^2 = 64
a = 8 cm
we know
diagonal of a square = root(2) a
= root(2) x 8
= root(2) x 2root(2)
= 4 cm
a^2 = 64
a = 8 cm
we know
diagonal of a square = root(2) a
= root(2) x 8
= root(2) x 2root(2)
= 4 cm
maria9:
mark my answer as brainliest... Thank Q
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↪ Question : find the side and diagonal of a square whose area area is 64 cm² ?
↪ Method of Solution :
↪ Given: Area of Square = 64 cm²
↪ (Side)² = 64
↪ Side = √64
↪ Side = 8 cm
Now, According to the Question's Statement!
➡ Statement : find the side and diagonal of a square!
↪Diagonal of Square = √2a
↪Diagonal of Square = √2 × 8
↪Diagonal of Square = 1.41 × 8
↪ Diagonal of Square = 11.28 cm²
▶Hence, Required Diagonal of Square is 11.28 cm²▶
↪ Method of Solution :
↪ Given: Area of Square = 64 cm²
↪ (Side)² = 64
↪ Side = √64
↪ Side = 8 cm
Now, According to the Question's Statement!
➡ Statement : find the side and diagonal of a square!
↪Diagonal of Square = √2a
↪Diagonal of Square = √2 × 8
↪Diagonal of Square = 1.41 × 8
↪ Diagonal of Square = 11.28 cm²
▶Hence, Required Diagonal of Square is 11.28 cm²▶
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