Question

find the side and perimeter of a square whose diagonls is 10 cm

Answer 1

HERE'S YOUR ANSWER......✌️✌️

DIAGONAL = 10cm

DIAGONAL OF A SQUARE = a √2

B.T.P,

a√2 = 10

=> a = 5√2

PERIMETER

= 4×5√2

= 20√2.

Answer 2

Here is your answer dear⤵️⤵️

Diagonal of a square = $\sqrt{2}$ × side

10 = $\sqrt{2}$ × side

$\frac{10}{\sqrt2}$ = side

5 $\sqrt{2}$ = side

Perimeter of square = 4 × side

i.e. 4×5 $\sqrt{2}$

20 $\sqrt{2}$