Question

find the side of a parallelogram with one of its side is longer than the other by 15 cm and its perimeter is 108 CM.​

Answer 1

let first side be x cm

2nd side=(x+15) cm

Perimeter=2*side1 + 2*side2

108=2x + 2*(x+15)

108= 2x + 2x +30

108-30=4x

78=4x

x=78/4

x=19.5 cm

side1=19.5 cm

side2=19.5 +15

side2=  34.5 cm

Answer 2

Given :-

• Shape = Parallelogram
• One of its side is longer than the other by 15 cm
• Perimeter of Parallelogram = 108cm

To Find :-

• Measures of its Sides

Solution :-

Let the First Side be x cm

Then, the Second side will be x + 15 cm

According to the Question :-

➞ Perimeter = 2 (Sum of 2 Adjacent Sides)

➞ 108 = 2 ( x + x + 15 )

➞ 108 ÷ 2 = x + x + 15

➞ 54 = x + x + 15

➞ 54 = 2x + 15

➞ 54 - 15 = 2x

➞ 39 = 2x

➞ 39 ÷ 2 = x

➞ 19.5 = x

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Verification :-

➞ Perimeter = 2 (Sum of 2 Adjacent Sides)

➞ 108 = 2 ( x + x + 15 )

➞ 108 = 2 ( 19.5 + 19.5 + 15 )

➞ 108 = 2 ( 19.5 + 34.5 )

➞ 108 = 2 × 54

➞ 108 = 108

Hence Verified

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Therefore :-

• First Side = x = 19.5cm
• Second Side = x + 15 = 34.5cm

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★ Additional Info :

Formulas Related to Parallelogram :-

• Area of Parallelogram = Base × Height
• Base of Parallelogram = Area ÷ Height
• Height of Parallelogram = Area ÷ Base
• Perimeter of Parallelogram = 2 ( Sum of Adjacent Sides )

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