Math, asked by aparanashiraskar, 5 months ago

find the side of square whose diagonal is 25 root 2​

Answers

Answered by sunideeplala2008
1

Answer:

9) Sum \: of \: \frac{-8}{19} \:and \: \frac{-4}{57}9)Sumof

19

−8

and

57

−4

= \frac{-8}{19} +\Big( \frac{-4}{57}\Big)=

19

−8

+(

57

−4

)

= \frac{-8}{19} - \frac{4}{57}=

19

−8

57

4

= \frac{-24 - 4}{57}=

57

−24−4

= \frac{-28}{57}=

57

−28

Therefore.,

\red{Sum \: of \: \frac{-8}{19} \:and \: \frac{-4}{57}}Sumof

19

−8

and

57

−4

\green { = \frac{-28}{57}}=

57

−28

Option \: \pink{ ( C ) } \: is \: correctOption(C)iscorrect

10) Given \: Rational \: numbers \: \frac{4}{9} , \frac{-5}{6} , \frac{-7}{-12} , \frac{11}{-24}10)GivenRationalnumbers

9

4

,

6

−5

,

−12

−7

,

−24

11

/* L.C.M of the Denominators 9,6,12 and 24 */

L.C.M (9,6,12,24 ) = 72L.C.M(9,6,12,24)=72

\begin{gathered}i) \frac{4}{9} \\= \frac{4\times 8}{9\times 8}\\ = \frac{32}{72}\end{gathered}

i)

9

4

=

9×8

4×8

=

72

32

\begin{gathered}ii) \frac{-5}{6} \\= \frac{-5\times 12}{6\times 12}\\ = \frac{-60}{72}\end{gathered}

ii)

6

−5

=

6×12

−5×12

=

72

−60

\begin{gathered}iii) \frac{-7}{-12} \\= \frac{7\times 6}{12\times 6}\\ = \frac{42}{72}\end{gathered}

iii)

−12

−7

=

12×6

7×6

=

72

42

\begin{gathered}iv) \frac{-11}{24} \\= \frac{-11\times 3}{24\times 3}\\ = \frac{-33}{72}\end{gathered}

iv)

24

−11

=

24×3

−11×3

=

72

−33

Therefore.,

\blue { \frac{-60}{72} \lt \frac{-33}{72} \lt \frac{32}{72 } \lt \frac{ 42}{72} }

72

−60

<

72

−33

<

72

32

<

72

42

\pink {\implies \frac{-5}{6} \lt \frac{-11}{24} \lt \frac{4}{9} \lt \frac{-7}{-12} }⟹

6

−5

<

24

−11

<

9

4

<

−12

−7

Therefore .,

Smallest \: rational \: number = \frac{-5}{6}Smallestrationalnumber=

6

−5

•••♪

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