Question

find the side of squares whose diagonal is 16√2 cm​

Answer 1

Answer:

16 cm

Step-by-step explanation:

$diagonal \: of \: square = \sqrt{2} \times side$

$16 \sqrt{2} = \sqrt{2} \times side \\ \frac{16 \sqrt{2} }{ \sqrt{2} } = side \\ 16 = side \\ side = 16 \: cm$

Answer 2

Answer:

16

Step-by-step explanation:

LET US TAKE THE SIDE OF SQUARE BE 'a'

SO ALL SIDES OF SQUARES HAVE SAME LENGTH 'a'

WE KNOW THAT DIAGONAL OF A SQUARE WHOSE SIDE IS 'a' IS

$a\sqrt{2}$

so GIVEN DIAGONAL IS 16√2

COMPARE THIS

16√2 = a√2

a=16

So the side of the square is 16.

we get a√2 by using the Pythagoras theorem for right angled triangle formed the diagonal and other two sides