Question

Find the sides marked with letters. All lengths are given in centimeters

Answer 1

Answer:

sorry i don't help you sorry for that

Answer 2

Answer:

$6)$ $x = 4 cm ; w =$ $\frac{3}{2} / 1\frac{1}{2}$ $cm$

$7) e = 9cm ; f = \frac{9}{2} / 4\frac{1}{2}$$cm$

Step-by-step explanation:

$6)$ First of all draw two similar triangles like in that image below.

In the triangles ACD aand ABE

A = A, C = B and D = E

We have  $\frac{CD}{BE}$ = $\frac{AC}{AB}$ = $\frac{AD}{AE}$

    $\frac{AD}{AE\\}$ = $\frac{CD}{BE}$

⇒ $\frac{x+2}{x}$ = $\frac{6}{4}$

'${x}$' is multiplied with 3.

⇒ ${x+2$ = $\frac{3x}{2}$

And '${2}$' is multiplied with $(x+2)$

⇒ $2(x+2)$ = $3x$

⇒ $2x + 4$ = $3x$

⇒ $4 = 3x - 2x$

⇒ $x = 4 cm$

   $\frac{AC}{AB} =\frac{CD}{BE}$

⇒ $\frac{w+3}{3} = \frac{6}{4}$

⇒ $w+3 = \frac{3}{2}$ × $3$

'$3$' is multiplied with $\frac{3}{2}$

⇒ $w = \frac{9}{2} - 3$

Subtract $3$ with $\frac{3}{2}$ which was multiplied with $3$ and became $\frac{9}{2}$

⇒ $w = 1\frac{1}{2}$ $cm$ / $\frac{3}{2}$ $cm$

$7)$ Do the same with number 7, draw two similar triangle like the image below.

In the triangles ACD aand ABE  

A = A, C = B and D = E

We have, $\frac{AC}{AB} =\frac{AD}{AE} =\frac{BE}{CD}$

   $\frac{AD}{AE} = \frac{AC}{AB}$

⇒ $\frac{(e+3)}{e} = \frac{8}{6}$

'${x}$' is multiplied with 3.

⇒ $e+3 = \frac{4e}{3}$

And '${2}$' is multiplied with $(x+2)$

⇒ $3(e+3) = 4e$

⇒ $3e+9 = 4e$

⇒ $9= 4e-3e$

⇒ $e = 9 cm$

   $\frac{BE}{CD} =\frac{AB}{AC}$  { For this equation I swap both of the equations)

⇒ $\frac{f}{6}=\frac{6}{8}$

Multiply $6$ with  $\frac{3}{4}$

⇒ $f = \frac{3}{4}$ × $6$

⇒ $f = \frac{9}{2} / 4\frac{1}{2}$ $cm$

I hope this was helpful and pardon my mistakes. Please make me brainleist if u find this helpful. Thanks.!