find the sides of an isosceles triangle whose perimeter equal to 56 cm and third side is 14 cm
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Hey friend...!!!
Let the sides be x and x
Third side = 14 cm
Perimeter = 56 cm
So,
X + x + 14 = 56
2x + 14 = 56
2x = 56 - 14
2x = 42
X = 42/2
X = 21
So,the length of the sides are 21cm and 21cm.
Hope it helps...!!!
Let the sides be x and x
Third side = 14 cm
Perimeter = 56 cm
So,
X + x + 14 = 56
2x + 14 = 56
2x = 56 - 14
2x = 42
X = 42/2
X = 21
So,the length of the sides are 21cm and 21cm.
Hope it helps...!!!
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