Question

Find the sides of the ∆ AOB in the following figure where the side of the sq. is 4m. [Angle O is the point of intersection of Diagonals]​​

Answer 1

Answer:

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now as quadrilateral abcd is square

it's all sides would be equal

ie ab=bc=cd=ad=4 cm

now here bd and ac are diagonals of square

so as we know that diagonal of square=root 2×side

ie ac=4root 2 and bd=4 root 2

now moreover since diagonals of square bisect each other

ao=oc and bo=do

ie ao=oc=4rooot 2/2

and bo=od=4root 2/2

ie ao=oc=2root 2 and bo=do=2root 2

so here ao and bo are constituent sides of triangle aob

so hence the remaining missing sides of triangle aob are 2root 2 cm each along with base ab as 4 cm

so hence triangle aob is an isoceles triangle as two sides except base are equal in length