Question

Find the simple interest and amount on: Rs 150 for 4 years at 5% per year.​

Answer 1

Answer :-

• The simple interest is Rs 30.
• Amount = Rs 180.

Given :-

• Principal = Rs 150.
• Rate = 5% per annum.
• Time = 4 years.

To find :-

• The simple interest and amount.

Step-by-step explanation :-

• Before finding the amount, let's find the simple interest!

We know that :-

$\underline{\boxed{\sf SI = \dfrac{Principal \times Rate \times Time}{100}}}$

Here,

• Principal = Rs 150.
• Rate = 5% per annum.
• Time = 4 years.

Hence,

$\longmapsto\rm SI = \dfrac{150 \times 5 \times 4}{100}$

Cutting off the zeroes,

$\longmapsto\rm SI = \dfrac{15 \times 5 \times 4 }{10}$

Reducing the numbers,

$\longmapsto\rm SI = \dfrac{15 \times 1 \times 2}{1}$

Now let's multiply the remaining numbers since we can't reduce them anymore.

$\longmapsto\rm SI = 15 \times 1 \times 2$

Multiplying the numbers,

$\longmapsto\overline{\boxed{\rm SI = Rs \: 30}}$

--------------------

• Now let's find the amount, as we know the simple interest!

We know that :-

$\underline{\boxed{\sf Amount = Principal + Interest}}$

Here,

• Principal = Rs 150.
• Interest = Rs 30.

Hence,

$\boxed{\bf Amount = 150 + 30}$

$\overline{\boxed{\bf Amount = Rs \: 180}}$

Answer 2

Given :

• Rs 150 for 4 years at 5% per year.

To find :

• Simple interest and amount

Formual used :

$\underline{\boxed{\sf SI = \dfrac{Principal \times Rate \times T}{100}}}$

Solution :

Rs.150 for 4 years at 5% per years.

We know that ,

P = Rs.150

Now ,

R = 5% per years

T = 4 years

Here ,

$\sf \frac{S.I =( P × R × T) }{100}$

$\sf Substituting \: the \: values = \\ \sf \frac{(150 × 5 × 4)}{100} = Rs 30$

Amount = P + S.I

$\sf Substituting \: the \: values \: \\\sf = 150 + 30 = Rs.180$