Question

Find the simple interest and amount when principal =6400,rate =6percent p. a. and time =2years.

Answer 1

Answer: 768

Step-by-step explanation:

Simple interest = principal × rate × time ÷100

Simple interest =6400×6 ×2÷100

Simple interest =76800÷100=768

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Simple\:interest=768\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Time (t)= 2\: years} \\ \\ : \implies \text{Principal(p) = 6400\:rupees} \\ \\ : \implies \text{Rate(r) = 6\%} \\ \\ \red{ \underline \bold{To \: Find: }} \\ : \implies \text{Simple\:interest(S.I) = ?}$

• According to given question :

$\bold{As \: we \: know \: that } \\ \circ \: \text{Simple \: interest} = \frac{ \text{Principal }\times \text{ Rate} \times \text{Time}}{100} \\ \\ \bold{Putting \: given \: values} \\ : \implies S.I = \frac{p \times r \times t}{100} \\ \\ : \implies S.I = \frac{6400 \times 6 \times2}{100} \\ \\ : \implies S.I = \frac{6400\times 12 }{100} \\ \\ \green{ : \implies \text{S.I= 768\: rupees}} \\ \\ \green{ \therefore \text{Simple\:interest =768\: rupees}} \\ \\ \bold{Basic \: formula\:related\:to\:C.I} \\ \circ \: A = p(1 + \frac{r}{100} )^{t}$