Question

find the simple interest and the amount on ₹4000 for 2 years at per annum​

Answer 1

Answer:

For ,

N=2years

R=10 %

P=Rs4,000

We have S.I.=

100

PNR

=

100

4,000×2×10

=Rs800

And on interest being compounded for 2 years and R=10 %, Amount=P(1+

100

R

)

N

=4,000×(1+

100

10

)

2

=4,000×1.1×1.1=Rs.4,840

So, C.I.=A−P=4,840−4,000=840

And required difference C.I.−S.I.=840−800=Rs40

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